C Source Code Formatting Show

SourceFormatX Code Formatter bases on powerful syntax parse engines so it can beautify and format source code files with omnifarious styles, even these unorderly source code examples below:

  C/C++ Source Code Formatting Examples:     Example 1   |   Example 2   |   Example 3   |   Example 4   |   Example 5

This C source code comes from IOCCC too, source code was arranged like three letters: CRC.

  /* Before C/C++ Code Formatting */

  #include <stdio.h>
  #include <stdlib.h>

  int main(int a,char     **A){FILE*B;typedef     unsigned long C;C b
  [8]; if(!(a==7&&(B=     fopen(1[A],"rb"))))     return 1;for(7[b]=0
  ;7[b]<5;7[b]++)b[7[     b]]=strtoul(A[2+7[b     ]],0,16-!7[b]*6);5[
  b]=3[b]                 ; while     ((6[b]=     getc(B)
  )!=(C)-                 1){if(2     [b])for     (7[b]=0
  ;7[b]<4                 ;7[b]++     )if(((6     [b]>>7[
  b])^(6[                 b]>>(7-7[b])))&1)6[     b] ^=(1
  <<7[b])                 ^(1<<(7-7[b]));5[b]     ^= 6[b]
  <<(0[b]                 -8);for(7[b]=0;7[b]     <8;7[b]
  ++)if((                 5[b]>>(0[b]-            1))&1)5
  [b]=(5[                 b]<<1)^ 1[b];           else 5[
  b]<<=1;                 }5[b]&=((((C)1          <<(0[b]
  -1))-1)                 <<1)|1; if(2[b]         )for(7[
  b]=0;7[                 b]<(0[b  ]>>1);7        [b] ++)
  if(((5[b]>>7[b])^(5     [b]>>(0   [b]-1-7       [b])))&1)5[b]^=((C)
  1<<7[b])^((C)1<<(0[     b]-1-7[    b]));5[      b]^=4[b];fclose(B);
  printf("%0*lX\n", (     int)(0[     b]+3)>>     2,5[b]); return 0;}

  /* After C/C++ Code Formatting */

  #include <stdio.h>
  #include <stdlib.h>

  int main(int a, char** A)
  {
    FILE* B;
    typedef unsigned long C;
    C b[8];
    if (!(a == 7 && (B = fopen(1[A], "rb"))))
      return 1;
    for (7[b] = 0; 7[b] < 5; 7[b]++)
      b[7[b]] = strtoul(A[2 + 7[b]], 0, 16 - !7[b]* 6);
    5[b] = 3[b];
    while ((6[b] = getc(B)) != (C) - 1)
    {
      if (2[b])
        for (7[b] = 0; 7[b] < 4; 7[b]++)
          if (((6[b] >> 7[b]) ^ (6[b] >> (7 - 7[b]))) & 1)
            6[b] ^= (1 << 7[b]) ^ (1 << (7 - 7[b]));
      5[b] ^= 6[b] << (0[b] - 8);
      for (7[b] = 0; 7[b] < 8; 7[b]++)
        if ((5[b] >> (0[b] - 1)) & 1)
          5[b] = (5[b] << 1) ^ 1[b];
        else
          5[b] <<= 1;
    }
    5[b] &= ((((C)1 << (0[b] - 1)) - 1) << 1) | 1;
    if (2[b])
      for (7[b] = 0; 7[b] < (0[b] >> 1); 7[b]++)
        if (((5[b] >> 7[b]) ^ (5[b] >> (0[b] - 1 - 7[b]))) & 1)
          5[b] ^= ((C)1 << 7[b]) ^ ((C)1 << (0[b] - 1 - 7[b]));
    5[b] ^= 4[b];
    fclose(B);
    printf("%0*lX\n", (int)(0[b] + 3) >> 2, 5[b]);
    return 0;
  }

Example 1   |   Example 2   |   Example 3   |   Example 4   |   Example 5

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